Determining Secant Value Given Tangent Squared An Exploration Of Trigonometric Identities

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In the realm of trigonometry, the interplay between trigonometric functions like tangent and secant often presents intriguing challenges. This article delves into a specific problem: given that tan2θ=38\tan^2 \theta = \frac{3}{8}, we aim to determine the value of secθ\sec \theta. This exploration will not only provide the solution but also illuminate the fundamental relationships between trigonometric functions and the importance of considering all possible solutions.

Leveraging the Pythagorean Identity: The Key to Unlocking the Solution

The cornerstone of solving this problem lies in the Pythagorean identity, a fundamental equation in trigonometry that connects sine, cosine, and consequently, tangent and secant. The identity states:

sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

This identity can be manipulated to relate tangent and secant. Dividing both sides of the equation by cos2θ\cos^2 \theta, we get:

sin2θcos2θ+cos2θcos2θ=1cos2θ\frac{\sin^2 \theta}{\cos^2 \theta} + \frac{\cos^2 \theta}{\cos^2 \theta} = \frac{1}{\cos^2 \theta}

Since tanθ=sinθcosθ\tan \theta = \frac{\sin \theta}{\cos \theta} and secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}, the equation transforms into:

tan2θ+1=sec2θ\tan^2 \theta + 1 = \sec^2 \theta

This powerful identity directly links the square of the tangent function to the square of the secant function, providing a pathway to solve our problem.

Now, we are given that tan2θ=38\tan^2 \theta = \frac{3}{8}. Substituting this value into the identity, we obtain:

38+1=sec2θ\frac{3}{8} + 1 = \sec^2 \theta

Simplifying the left side of the equation:

38+88=sec2θ\frac{3}{8} + \frac{8}{8} = \sec^2 \theta

118=sec2θ\frac{11}{8} = \sec^2 \theta

To find the value of secθ\sec \theta, we take the square root of both sides:

secθ=±118\sec \theta = \pm \sqrt{\frac{11}{8}}

The crucial point here is the presence of the ±\pm sign. This signifies that there are two possible values for secθ\sec \theta, one positive and one negative. This arises because squaring either a positive or a negative number results in a positive number. Therefore, when taking the square root, we must consider both possibilities.

Delving Deeper: Understanding the Sign of Secant

The sign of secθ\sec \theta depends on the quadrant in which the angle θ\theta lies. Recall that secant is the reciprocal of cosine:

secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}

Cosine is positive in the first and fourth quadrants, and negative in the second and third quadrants. Consequently, secant follows the same sign convention:

  • Quadrant I: cosθ>0\cos \theta > 0, secθ>0\sec \theta > 0
  • Quadrant II: cosθ<0\cos \theta < 0, secθ<0\sec \theta < 0
  • Quadrant III: cosθ<0\cos \theta < 0, secθ<0\sec \theta < 0
  • Quadrant IV: cosθ>0\cos \theta > 0, secθ>0\sec \theta > 0

Since we are given tan2θ=38\tan^2 \theta = \frac{3}{8}, we know that tanθ\tan \theta can be either positive or negative. Tangent is positive in the first and third quadrants, and negative in the second and fourth quadrants.

  • If tanθ\tan \theta is positive: θ\theta lies in either Quadrant I or Quadrant III. In Quadrant I, secθ\sec \theta is positive, while in Quadrant III, secθ\sec \theta is negative. Thus, both 118\sqrt{\frac{11}{8}} and 118-\sqrt{\frac{11}{8}} are possible values.
  • If tanθ\tan \theta is negative: θ\theta lies in either Quadrant II or Quadrant IV. In Quadrant II, secθ\sec \theta is negative, while in Quadrant IV, secθ\sec \theta is positive. Again, both 118\sqrt{\frac{11}{8}} and 118-\sqrt{\frac{11}{8}} are possible values.

Therefore, without additional information about the quadrant of θ\theta, we must consider both positive and negative solutions for secθ\sec \theta.

The Definitive Answer: Embracing the Duality

Based on our exploration and the application of the Pythagorean identity, we have conclusively determined that the value of secθ\sec \theta is ±118\pm \sqrt{\frac{11}{8}}. This encapsulates both the positive and negative possibilities, reflecting the inherent duality arising from the squared trigonometric functions.

Therefore, the correct answer is B. ±118\pm \sqrt{\frac{11}{8}}. This solution highlights the importance of considering all possible solutions when dealing with trigonometric equations, especially when squares are involved.

Beyond the Solution: Exploring the Broader Context of Trigonometric Identities

This problem serves as a microcosm of the broader world of trigonometric identities. These identities are not merely abstract equations; they are fundamental tools that underpin a vast array of applications in mathematics, physics, engineering, and other scientific disciplines. Mastering these identities is crucial for anyone seeking a deep understanding of these fields.

Trigonometric identities provide a framework for simplifying complex expressions, solving equations, and establishing relationships between different trigonometric functions. They are essential for tasks such as:

  • Solving trigonometric equations: Identities allow us to manipulate equations into solvable forms, finding the angles that satisfy given conditions.
  • Simplifying expressions: Complex trigonometric expressions can often be simplified using identities, making them easier to work with.
  • Proving other identities: Many trigonometric identities are derived from the fundamental identities, demonstrating the interconnectedness of the subject.
  • Calculus: Trigonometric identities play a crucial role in integration and differentiation of trigonometric functions.
  • Physics and Engineering: These identities are extensively used in analyzing oscillations, waves, and other periodic phenomena.

By understanding and applying trigonometric identities, we unlock a powerful toolbox for tackling a wide range of problems. The problem we addressed in this article, finding secθ\sec \theta given tan2θ\tan^2 \theta, exemplifies the utility and elegance of these identities.

Key Takeaways: Solidifying Our Understanding

Before we conclude, let's summarize the key takeaways from our exploration:

  1. The Pythagorean Identity is Paramount: The identity tan2θ+1=sec2θ\tan^2 \theta + 1 = \sec^2 \theta is crucial for relating tangent and secant.
  2. Embrace the ±\pm Sign: When taking square roots, remember to consider both positive and negative solutions.
  3. Quadrant Awareness is Key: The sign of secθ\sec \theta depends on the quadrant in which θ\theta lies.
  4. Trigonometric Identities are Tools: They are powerful tools for simplifying expressions, solving equations, and establishing relationships.
  5. Context Matters: Without additional information about the angle's quadrant, both positive and negative solutions for secant must be considered.

By keeping these points in mind, you'll be well-equipped to tackle similar problems and further explore the fascinating world of trigonometry.

In conclusion, determining the value of secθ\sec \theta given tan2θ=38\tan^2 \theta = \frac{3}{8} requires a careful application of the Pythagorean identity and a thorough consideration of the possible signs of secant based on the angle's quadrant. The solution, ±118\pm \sqrt{\frac{11}{8}}, underscores the importance of embracing duality and understanding the fundamental relationships between trigonometric functions. This exploration not only solves the specific problem but also highlights the broader significance of trigonometric identities in mathematics and its applications.